The following is the syllabus for the Analytical Reasoning:
Topic | Subtopics |
---|---|
Introduction to Analytical Reasoning | Definition, Importance |
Deductive Reasoning | Principles, Examples |
Inductive Reasoning | Principles, Examples |
Abductive Reasoning | Principles, Examples |
Critical Thinking | Elements, Application |
Pattern Recognition | Data, Sequences, Structures |
Logical Reasoning | Formal Logic, Rules |
Spatial Reasoning | Visual Manipulation, Shapes |
Causal Reasoning | Cause-and-Effect Relationships |
Decision-Making | Evaluation, Informed Choices |
Scientific Method | Steps, Experimental Design |
Integration and Practical Applications | Real-world Problem-Solving |
Review and Assessment | Practice Problems, Discussions |
Final Exam | Comprehensive Assessment |
Solving Analytical Reasonging problems not only make you good at solving questions for exams but also it teaches you how to think critically in daily life. Here’s the 5 tips that will help you in solving the analytical reasoning questions in efficient way.
Understand the question very deeply and don’t jump right in without understanding the details and any specific instructions giving in question.
Identifiy the the terms that will lead in solving the problems. Look for relationships, conditions, and constraints that will guide the analysis.
Use diagrams, charts, or tables to visualize the information. These will help you in Creating visual representation and building relation ship in order to solve the problems.
Break Down the complex problems and solve indivusually.
Approach the question in styp by step Process while solving the analytical reasoning question
It is like when certain things are true how it impact in the scenario.
Practice practice and Practice! It will help you solving problems subconciously and as a result you will be able to solve the Analytical reasoning question faster in the Exam.
1. Find the number of maximum possible triangles in the below figure.
maximum possible triangles
Options: A. 10 B. 19 C. 23 D. 21
maximum possible triangles solutions
Number of direct/ simple triangles = 10 Number of triangles composed of two points each = 7 Number of triangles composed of four points each = 4 Total number of triangles = 10+ 7 + 4 = 21
2. Determine how many straight lines are necessary to create the given figure.
Options: A. 9 B. 11 C. 15 D. 16
Required horizontal lines are DE, FH, IL and BC i.e. 4 Required slanting lines are AC, DO, FN, IM, AB, EM and HN i.e. 7. Total number of required lines = 11
3. Count the number of rectangles in the below figure.
Option: A. 19 B. 16 C. 30 D. 34
Simple rectangles = 8 (VWON, OBAN,XYQP,PQCB, CRSD, RZA1S,DTUA,B1C1UT) Rectangles combining 2 Components = 8 (ABJL,BCKI,JCDL,KDAI,EFCA,BFGD,CGHA,DHEB) Squares combining 2 components = 4 (BJMI, CKMJ , DLMK and AIML). Squares combining 3 components = 4( EBMA, BFCM, MCGD and AMDH). Squares combining 4 components = 4( VWBA, XYCB, ZA1DC and B1C1AD ). Squares combining 7 components = 4( NOJL, PQKI, RSLJ and TULK). Squares combining 8 components = 1 (ABCD). Squares combining 12 components = 1 (EFGH). Hence, total number of rectangles = 4 + 4 + 4 + 4 + 1 + 1 +8+8 = 34
4. Count the number of squares and triangles in the given figure.
A. 28 triangles, 10 squares B. 28 triangles, 8 squares C. 32 triangles, 10 squares D. 32 triangles, 8 squares
Triangle : The eight most basic triangles are IJQ, JKQ, KLQ, LMQ, MNQ, NOQ, OPQ, and PIQ. There are 12 triangles who has 2 compoents = ABQ, BCQ, CDQ, DEQ, EFQ, FGQ, GHQ, HAQ, IKQ, KMQ, MOQ, and OIQ. There are 12 triangles who has 4 compoents = ACQ, CEQ, EGQ, GAQ, IKM, KMO, MOI and OIK. There are 8 triangles who has 8 compoents = ACE, CEG, EGA and GAC ∴ Total number of triangles in the figure : 8 + 12 + 8 + 4 = 32. Squares : Four squares consist of two components each, which are IJQP, JKLQ, QLMN, and PQNO. Similarly, there are four squares composed of four components each, which are ABQH, BCDQ, QDEF, and HQFG. There is only one square consisting of eight components, which is IKMO. Moreover, there is only one square made up of sixteen components, which is ACEG. The figure contains a total of 10 squares. Hence, option C is correct.
Q 5. Calculate a number of triangles.
Option. A. 8 B. 7 C. 6 D. 5
Question 6. Calculate the number of quadrilaterals in the below figure.
Options: (A) 15 (B) 18 (C) 19 (D) 21
Quadrilateral: Any closed shape which has 4 sides is called as quadrilateral. Now, we have to count 4 sided closed shape. No. of square=5 No. of rectangle=4 Shape with 4 sides= 9 Totall =18
Q 7. Calculate a number of rhombus in the below figure.
Question 8: Count number of squares.
Simple squares: 10 Combined squares: 6 (Note: Don’t count the center Square twice)
Total : 16.
Question 8: Count sum of triangles and square.
Triangle = 12+7+4 =23
Square= 6+3=9
Answer is 32
Question 9: Count parallogram in the below figure.
Remember parallogram is trapezium, but vice versa is not true.
In conclusion, Analytical Reasoning is an essential skill for the SSC CGL exam. Candidates should develop their observation and visual skills, practice regularly, and manage their time effectively to excel in this section. With the right approach and dedicated effort, anyone can improve their Non-Verbal Reasoning skills and score well in the SSC CGL exam.
All the Best!!!
What is the nature of analytic reasoning.
Analytical reasoning based questions judge a person’s ablity to identify patterns and visualize them.
It is not something, which one can study and learn, you need to practise questions thoroughly and practise visualizing the patterns.
It differs from one exam to other, any number of questions can be asked.
In analytical reasoning based question one needs to use their analytical skills where as in logical questions one needs to use mental ability.
Similar reads.
Find the number of triangles in the given figure.
The simplest triangles are AML, LRK, KWD, DWJ, JXI, IYC, CYH, HTG, GOB, BOF, FNE and EMA i.e. 12 in number.
The triangles composed of two components each are AEL, KDJ, HIC and FBG i.e. 4 in number.
The triangles composed of three components each are APF, EQB, BQH, GVC, CVJ, IUD, DUL and KPA i.e. 8 in number.
The triangles composed of six components each are ASB, BSG, CSD, DSA, AKF, EBH, GGJ and IDL i.e. 8 in number.
The triangles composed of twelve components each are ADB, ABC, BCD and CDA i.e. 4 in number.
Total number of triangles in the figure = 12 + 4 + 8 + 8 + 4 = 36.
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Find the minimum number of straight lines required to make the given figure.
The horizontal lines are AK, BJ, CI, DH and EG i.e. 5 in number.
The vertical lines are AE, LF and KG i.e. 3 in number.
The slanting lines are LC, CF, FI, LI, EK and AG i.e. 6 in number.
Thus, there are 5 + 3 + 6 = 14 straight lines in the figure.
Choose the alternative which is closely resembles the water image of the given combination/figure.
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What is the number of straight lines and the number of triangles in the given figure.
The Horizontal lines are DF and BC i.e. 2 in number.
The Vertical lines are DG, AH and FI i.e. 3 in number.
The Slanting lines are AB, AC, BF and DC i.e. 4 in number.
Thus, there are 2 + 3 + 4 = 9 straight lines in the figure.
Now, we shall count the number of triangles in the figure.
The simplest triangles are ADE, AEF, DEK, EFK, DJK, FLK, DJB, FLC, BJG and LIC i.e. 10 in number.
The triangles composed of two components each are ADF, AFK, DFK, ADK, DKB, FCK, BKH, KHC, DGB and FIC i.e. 10 in number.
The triangles composed of three components each are DFJ and DFL i.e. 2 in number.
The triangles composed of four components each are ABK, ACK, BFI, CDG, DFB, DFC and BKC i.e. 7 in number.
The triangles composed of six components each are ABH, ACH, ABF, ACD, BFC and CDB i.e. 6 in number.
There is only one triangle i.e. ABC composed of twelve components.
There are 10 + 10 + 2 + 7 + 6+ 1 = 36 triangles in the figure.
What is the number of triangles that can be formed whose vertices are the vertices of an octagon but have only one side common with that of octagon?
When the triangles are drawn in an octagon with vertices same as those of the octagon and having one side common to that of the octagon, the figure will appear as shown in (Fig. 1).
Now, we shall first consider the triangles having only one side AB common with octagon ABCDEFGH and having vertices common with the octagon (See Fig. 2).Such triangles are ABD, ABE, ABF and ABG i.e. 4 in number.
Similarly, the triangles having only one side BC common with the octagon and also having vertices common with the octagon are BCE, BCF, BCG and BCH (as shown in Fig. 3). i.e. There are 4 such triangles.
This way, we have 4 triangles for each side of the octagon. Thus, there are 8 x 4 = 32 such triangles.
Count the number of triangles and squares in the given figure.
The figure may be labelled as shown
Triangles :
The Simplest triangles are BGM, GHM, HAM, ABM, GIN, IJN, JHN, HGN, IKO, KLO, LJO, JIO, KDP, DEP, ELP, LKP, BCD and AFE i.e 18 in number
The triangles composed of two components each are ABG, BGH, GHA, HAB, HGI, GIJ, IJH, JHG, JIK, IKL, KLJ,LJI, LKD, KDE, DEL and ELK i.e 16 in number.
The triangles composed of four components each are BHI, GJK, ILD, AGJ, HIL and JKE i.e 6 in number.
Total number of triangles in the figure = 18 + 16 + 6 =40.
The Squares composed of two components each are MGNH, NIOJ, and OKPL i.e 3 in number
The Squares composed of four components each are BGHA, GIJH, IKJL and KDEL i.e 4 in number
Total number of squares in the figure = 3 + 4 =7
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Find the number of triangles in the given figure ?
The given figure can be labelled as :
The simplest triangles are AJF, FBG, HDI, GCH and JEI i.e 5 in number. The triangles composed of the three components each are AIC, FCE, ADG, EBH and DJB i.e 5 in number. Thus, there are 5 + 5 = 10 triangles in the given figure.
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The simplest triangles are AKI, AIL, EKD, LFB, DJC, DKJ, KIJ, ILJ, JLB, BJC, DHC and BCG i.e. 12 in number. The triangles composed of two components each are AKJ, ALJ, AKL, ADJ, AJB and DBC i.e. 6 in number. The triangles composed of the three components each are ADC and ABC i.e. 2 in number. There is only one triangle i.e. ADB composed of four components. Thus, there are 12 + 6 + 2 + 1 = 21 triangles in the figure.
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