• <cassert> (assert.h)
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  • <cerrno> (errno.h)
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Containers:

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Input/Output:

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Multi-threading:

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non-member overloads

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std:: vector ::operator=

copy (1)
copy (1)
move (2)
initializer list (3)

Return value

main () { std::vector< > foo (3,0); std::vector< > bar (5,0); bar = foo; foo = std::vector< >(); std::cout << << (foo.size()) << ; std::cout << << (bar.size()) << ; 0; }

Iterator validity

Exception safety.

21.12 — Overloading the assignment operator

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Move Constructors and Move Assignment Operators (C++)

  • 9 contributors

This topic describes how to write a move constructor and a move assignment operator for a C++ class. A move constructor enables the resources owned by an rvalue object to be moved into an lvalue without copying. For more information about move semantics, see Rvalue Reference Declarator: && .

This topic builds upon the following C++ class, MemoryBlock , which manages a memory buffer.

The following procedures describe how to write a move constructor and a move assignment operator for the example C++ class.

To create a move constructor for a C++ class

Define an empty constructor method that takes an rvalue reference to the class type as its parameter, as demonstrated in the following example:

In the move constructor, assign the class data members from the source object to the object that is being constructed:

Assign the data members of the source object to default values. This prevents the destructor from freeing resources (such as memory) multiple times:

To create a move assignment operator for a C++ class

Define an empty assignment operator that takes an rvalue reference to the class type as its parameter and returns a reference to the class type, as demonstrated in the following example:

In the move assignment operator, add a conditional statement that performs no operation if you try to assign the object to itself.

In the conditional statement, free any resources (such as memory) from the object that is being assigned to.

The following example frees the _data member from the object that is being assigned to:

Follow steps 2 and 3 in the first procedure to transfer the data members from the source object to the object that is being constructed:

Return a reference to the current object, as shown in the following example:

Example: Complete move constructor and assignment operator

The following example shows the complete move constructor and move assignment operator for the MemoryBlock class:

Example Use move semantics to improve performance

The following example shows how move semantics can improve the performance of your applications. The example adds two elements to a vector object and then inserts a new element between the two existing elements. The vector class uses move semantics to perform the insertion operation efficiently by moving the elements of the vector instead of copying them.

This example produces the following output:

Before Visual Studio 2010, this example produced the following output:

The version of this example that uses move semantics is more efficient than the version that does not use move semantics because it performs fewer copy, memory allocation, and memory deallocation operations.

Robust Programming

To prevent resource leaks, always free resources (such as memory, file handles, and sockets) in the move assignment operator.

To prevent the unrecoverable destruction of resources, properly handle self-assignment in the move assignment operator.

If you provide both a move constructor and a move assignment operator for your class, you can eliminate redundant code by writing the move constructor to call the move assignment operator. The following example shows a revised version of the move constructor that calls the move assignment operator:

The std::move function converts the lvalue other to an rvalue.

Rvalue Reference Declarator: && std::move

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Vector with move constructor and move assignment operator [closed]

Please verify whether the code for a move constructor and a move assignment operator is correct.

  • memory-management

Jamal's user avatar

  • \$\begingroup\$ This isn't that kind of code review; take the tour , see How to Ask . If you aren't certain it works, test it. \$\endgroup\$ –  jonrsharpe Commented Apr 2, 2017 at 8:54

Default constructor

Stop trying to save space like that. THe point of good coding is to make it readable by humans. The computer can read any style so try and make it more maintainable by making it readable.

I would write it like this:

Sure you can use nullptr for the zero sized array. But this seems like a premature optimization. You can make the rest of your code less complicated by never having a null m_pInt . If there is never a null then your code does not need to check for it.

Also currently you have different behavior for:

Constructor

Sure this works. But std::cout is not the only stream you way want to print too

So I would pass a stream to print() . It can default to std::cout . Then you should add an operator<< . As the normal way of printing something is via << .

Note: prefer "\n" to std::endl . The difference is a stream flush. The stream will already flush itself when required. So you adding extra flushes is only going to cause the flushes to be less optimal.

Copy Constructor

Move constructor.

Yes that works. But you should also mark the move constructor as noexcept . The standard containers have optimizations that can be applied if they know tour class will not throw when being moved. Otherwise they have to fallback to copying to provide the strong exception guarantee.

The standard technique is to use swap though. It makes it look and behave just like move assignment. See below.

Copy Assignment

Yes the test for self assignment looks like a good optimization.

BUT its not. Self assignment happens so rarely (in fact basically never in real code) that what you are doing is pesimizing the normal flow and as a result will make your code slower. You do need to cope with self assignment but because it is so rare you don't need to worry that it is not the optimal path.

The second issue I have here is that you destroy the local data before you have a copy of the new data ready.

If something goes wrong in the rest of your code then you will be unable to roll back the state and thus can not provide the strong exception guarantee. When copying an object it should happen in three distict phases.

So your Copy assignment should look like this:

If you look carefully at those three stages. Stage 1 looks like the constructor and stage 3 looks like the destructor and stage 2 looks like a standard swap function so we can simplify the above to exactly that:

This is called the copy and swap idiom.

Move Assignment

Again the pesimizing test for self assignment.

The standard move assignment is to swap the source and the destination. This has a couple of benefits.

  • You don't call delete (and thus don't invoke the destructor). Thus it is potentially faster.
  • Because you did not delete the data there is an opportunity for it to be reused.
  • If the source is going out of scope it will invoke its destructor and destroy your data but it will be done after the completion of your object thus giving you strong exception guarantee. Thus allowing you to make your assignment operator noexcept.

Standard Move Assignment

I wrote a series of posts about all this.

Vector - Resource Management Allocation Vector - Resource Management Copy Swap Vector - Resize Vector - Simple Optimizations Vector - the Other Stuff

Loki Astari's user avatar

  • \$\begingroup\$ Hi. What do you mean by "Stop trying to save space like that." regarding the code MyVector():m_Size(0), m_pInt(nullptr) { } ? What would you write instead if this was the only constructor? \$\endgroup\$ –  krismath Commented May 1, 2017 at 21:20
  • 2 \$\begingroup\$ @krismath: One initialization per line. The point is to write readable code not try and squeeze as many operations onto a single line as you can. Updating answer with how I would write it. \$\endgroup\$ –  Loki Astari Commented May 1, 2017 at 23:03
  • \$\begingroup\$ MyVector() could be noexcept if you allow for m_pInt being nullptr . That's worth the hassle easily. \$\endgroup\$ –  Deduplicator Commented May 1, 2017 at 23:16
  • 1 \$\begingroup\$ @Deduplicator Not sure a noexcept default constructor buys you anything. Are there any optimizations in the STL this will enable? If it does not gain you anything then why add the extra complexity to the rest of your code. Especially when it adds two different meanings for basically the same declaration MyVector x; /* nullptr but size 0*/ and MyVector y(0); /* Not nullptr but size 0*/ \$\endgroup\$ –  Loki Astari Commented May 1, 2017 at 23:31
  • \$\begingroup\$ Fantastic answer. 1. I wonder why didn't you add m_pInt = nullptr in the destructor after deleting it. Omission? 2. In the ctor: MyVector(int x = 0) : m_size(0) . I believe you wanted to say m_size(x) here right? 3. I always tend to use {} instead of () for initialization of objects because it prevents widening and is more readable (doesn't look like a function call). \$\endgroup\$ –  KeyC0de Commented Oct 19, 2018 at 3:47

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Move Assignment Operator in C++ 11

In C++ programming, we have a feature called the move assignment operator, which was introduced in C++11. It helps us handle objects more efficiently, especially when it comes to managing resources like memory. In this article, we will discuss move assignment operators, when they are useful and called, and how to create user-defined move assignment operators.

Move Assignment Operator

The move assignment operator was added in C++ 11 to further strengthen the move semantics in C++. It is like a copy assignment operator but instead of copying the data, this moves the ownership of the given data to the destination object without making any additional copies. The source object is left in a valid but unspecified state.

User-Defined Move Assignment Operator

The programmer can define the move assignment operator using the syntax given below:

As you may have noticed, the move assignment operator function uses a special && reference qualifier. It represents the r-value references (generally literals or temporary values).

Usually, it returns a reference to the object (in this case, *this) so you can chain assignments together.

The move constructor is called by the compiler when the argument is an rvalue reference which can be done by std::move() function. 

Example of Move Assignment Operator

In this program, we will create a dynamic array class and create a user-defined move assignment operator.

                               

Explanation

The move assignment operator (operator=) is used to transfer resources from one DynamicArray object to another. It releases the current resources of the destination object, takes the resources from the source object, and leaves the source object in a valid but unspecified state.

In the main function:

  • We create two DynamicArray objects, arr1 with 5 elements and arr2 with 10 elements. We print their initial states.
  • We use the move assignment operator to transfer the resources from arr1 to arr2 by calling arr2 = std::move(arr1).
  • After the move, we print the states of both arr1 and arr2. arr1 is now in a valid but unspecified state, and arr2 contains the resources of arr1.
Note: We can also define a move constructor with a move assignment operator and reduce the code redundancy by calling the move assignment operator from the move constructor. To know about move constructor, refer to the article – Move Constructors in C++

Implicit Definition of Move Assignment Operator

The compiler also defines a default move assignment operator implicitly when the following conditions are satisfied:

  • No user-defined copy constructor is present.
  • No user-defined destructor is present.
  • No user-defined move constructor is present.

Need of Move Assignment Operator

In C++, objects can manage resources like memory. When we copy an object, it can be quite slow, especially if the object holds a lot of resources. Traditional copy operations create new copies, which can lead to unnecessary memory usage and slow down your program.

This is where move assignment operators come to the rescue. They let one object take over the resources of another, without making extra copies. This can significantly boost performance in scenarios like resizing arrays or returning objects from functions.

In contrast to the copy assignment operator, the end result of the move assignment operator will be a single copy of the source object.

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Overloading assignment operator with Classes and Vectors

I have a class defined:

and am trying to overload the assignment operator by such:

and I get the error code that buf is protected and length is protected. I'm not sure what I am missing. How can I properly overload the assignment operator with vectors and ints ?

  • operator-overloading

Thusitha Thilina Dayaratne's user avatar

  • 1 The implicitly-generated assignment operator does the same thing, so if you don't have anything else in the function besides what you have shown here then it'd be better to not define it yourself (or define as default in C++11) –  M.M Commented Aug 5, 2014 at 5:21

2 Answers 2

You do not need to provide any special member functions for your class, because the compiler synthesized ones will do the right thing in this case. The best option is to remove the assignment operator and copy constructor from your class definition.

juanchopanza's user avatar

You need to define the implementation as part of the class. You are missing the class specifier:

As written, you are defining a free operator overload (not bound to a class), and it's actually invalid to declare a free assignment operator overload anyway.

From the perspective of a free operator overload that isn't a member of String , buf and length are indeed inaccessible because they are private.

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c assignment operator vector

cppreference.com

Std::inplace_vector<t,n>:: insert_range.

(C++20)
(C++20)
(C++11)
(C++20)
(C++17)
(C++11)
(C++11)
Tables

inplace_vector::cbegin
inplace_vector::cend
inplace_vector::crbegin
inplace_vector::crend


erase_if(std::inplace_vector) (C++26)
operator<=> (C++26)

< <T> R >
constexpr iterator insert_range( const_iterator pos, R&& rg );
(since C++26)

Inserts, in non-reversing order, copies of elements in rg before pos .

Each iterator in the range rg is dereferenced exactly once.

rg must not overlap with the container. Otherwise, the behavior is undefined.

Parameters Return value Exceptions Example See also

[ edit ] Parameters

pos - iterator before which the content will be inserted (pos may be the iterator)
rg - a , that is, an whose elements are convertible to
Type requirements
- must be into from * (rg). Also, must be into and must satisfy , , and . Otherwise, the behavior is undefined.

[ edit ] Return value

An iterator that points at the copy of the first element inserted into inplace_vector or at pos if rg is empty.

  • std::bad_alloc , if ranges:: distance ( rg ) + size ( ) > capacity ( ) . The elements of * this are not modified.
  • Any exception thrown by insertion (i.e. by copy/move constructor, move/copy assignment operator of T ) or by any LegacyInputIterator operation. The elements of * this in the range [ ​ 0 ​ ,  pos ) are not modified.

[ edit ] Example

Possible output:

[ edit ] See also

inserts elements
(public member function)
adds a range of elements to the end
(public member function)
tries to add a range of elements to the end
(public member function)
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COMMENTS

  1. c++

    You can't, for example, use the assignment operator to copy from a std::list to a std::vector, or from one portion of a std::vector to another portion of the same std::vector.

  2. std::vector<T,Allocator>::operator=

    1) Copy assignment operator. Replaces the contents with a copy of the contents of other . If std::allocator_traits<allocator_type>::propagate_on_container_copy_assignment::value is true, the allocator of *this is replaced by a copy of other. If the allocator of *this after assignment would compare unequal to its old value, the old allocator is ...

  3. std::vector<T,Allocator>::assign

    std::vector<T,Allocator>:: assign. Replaces the contents of the container. 1) Replaces the contents with count copies of value value. 2) Replaces the contents with copies of those in the range [first,last). The behavior is undefined if either argument is an iterator into *this . This overload has the same effect as overload (1) if InputIt is an ...

  4. std::vector

    namespace pmr {. template<class T > using vector = std ::vector< T, std::pmr::polymorphic_allocator< T >>; } (2) (since C++17) 1)std::vector is a sequence container that encapsulates dynamic size arrays. 2)std::pmr::vector is an alias template that uses a polymorphic allocator. The elements are stored contiguously, which means that elements can ...

  5. Ways to copy a vector in C++

    In the above code, changing the value at one vector did not alter the value at another vector, hence they are not allocated at the same address, hence deep copy. Method 2: By assignment "=" operator. Simply assigning the new vector to the old one copies the vector. This way of assignment is not possible in the case of arrays.

  6. search

    x. A vector object of the same type (i.e., with the same template parameters, T and Alloc ). il. An initializer_list object. The compiler will automatically construct such objects from initializer list declarators. Member type value_type is the type of the elements in the container, defined in vector as an alias of its first template parameter ...

  7. 21.12

    21.12 — Overloading the assignment operator. Alex July 22, 2024. The copy assignment operator (operator=) is used to copy values from one object to another already existing object. As of C++11, C++ also supports "Move assignment". We discuss move assignment in lesson 22.3 -- Move constructors and move assignment .

  8. PDF Copy Constructors and Assignment Operators

    C++ handles object copying and assignment through two functions called copy constructors and assignment operators. While C++ will automatically provide these functions if you don't explicitly define them, in many cases you'll need to manually control how your objects are duplicated. This handout discusses copy constructors and assignment operators, including both high-level concepts and ...

  9. vector::operator= and vector::operator [ ] in C++ STL

    vector::operator= and vector::operator [ ] in C++ STL. Vectors are same as dynamic arrays with the ability to resize itself automatically when an element is inserted or deleted, with their storage being handled automatically by the container. This operator is used to assign new contents to the container by replacing the existing contents.

  10. Copy assignment operator

    the copy assignment operator selected for every non-static class type (or array of class type) member of T is trivial. A trivial copy assignment operator makes a copy of the object representation as if by std::memmove. All data types compatible with the C language (POD types) are trivially copy-assignable.

  11. Copy Constructor vs Assignment Operator in C++

    C++ compiler implicitly provides a copy constructor, if no copy constructor is defined in the class. A bitwise copy gets created, if the Assignment operator is not overloaded. Consider the following C++ program. Explanation: Here, t2 = t1; calls the assignment operator, same as t2.operator= (t1); and Test t3 = t1; calls the copy constructor ...

  12. c++

    If a class has a pointer we must do deep copy with assigment operator overloading (not shallow copy). Only if that pointer is a so-called "owning" pointer, i.e. if the class semantically owns the resource pointed at and is responsible for its eventual release or destruction. A pointer may also be a so-called "observing" pointer which points to ...

  13. Move Constructors and Move Assignment Operators (C++)

    This topic describes how to write a move constructor and a move assignment operator for a C++ class. A move constructor enables the resources owned by an rvalue object to be moved into an lvalue without copying. For more information about move semantics, see Rvalue Reference Declarator: &&. This topic builds upon the following C++ class ...

  14. Assignment operators

    Move assignment replaces the contents of the object a with the contents of b, avoiding copying if possible ( b may be modified). For class types, this is performed in a special member function, described in move assignment operator . (since C++11)

  15. C++ Assignment Operator Overloading

    The assignment operator,"=", is the operator used for Assignment. It copies the right value into the left value. Assignment Operators are predefined to operate only on built-in Data types. Assignment operator overloading is binary operator overloading. Overloading assignment operator in C++ copies all values of one object to another object.

  16. c++

    Please verify whether the code for a move constructor and a move assignment operator is correct. #include &lt;iostream&gt; using namespace std; class MyVector { size_t m_Size; int* m_pInt;

  17. c++

    1 Answer. Sorted by: 4. Yes, the assignment operator is overloaded for std::vector and you can safely use a = b; answered Apr 29, 2011 at 21:16. Kiril Kirov.

  18. Move assignment operator

    A move assignment operator is a non-template non-static member function with the name operator= that can be called with an argument of the same class type and copies the content of the argument, possibly mutating the argument.

  19. c++

    This answer is out of date -- as of C++11, standard containers all use copy/move constructors for non-assignment operations (like push_back), so do not require assignable objects unless you actually assign the container or a container element.

  20. Move Assignment Operator in C++ 11

    Move Assignment Operator The move assignment operator was added in C++ 11 to further strengthen the move semantics in C++. It is like a copy assignment operator but instead of copying the data, this moves the ownership of the given data to the destination object without making any additional copies. The source object is left in a valid but unspecified state.

  21. c++

    String& String::operator=(const String& input) {. buf = input.buf; length = input.length; return *this; } As written, you are defining a free operator overload (not bound to a class), and it's actually invalid to declare a free assignment operator overload anyway. From the perspective of a free operator overload that isn't a member of String ...

  22. std::inplace_vector<T,N>::insert_range

    Any exception thrown by insertion (i.e. by copy/move constructor, move/copy assignment operator of T) or by any LegacyInputIterator operation. The elements of * this in the range [ 0 , pos ) are not modified.